I need help with challenge 3 of 3

Question

I am unclear with what I am trying to write. I'm not sure how start=5 and reducing it by 1 comes into play. Can some show me the solution and explain it to me?

even.py

import random
start=5
def even_odd(num):
    random_number=random.randint(1,99)
    while True:
        if num % 2==0:
            print("{} is even".format(random_number))
        else:
            print("{} is odd".format(random_number))
    start=start-1 
    #If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

Answer 1 · 2017-09-28T17:36:52Z

September 28, 2017 5:36pm

Hi Natalie,

The key with this one is that you don't modify the even_odd() function. It has already been written for you and is complete as it is. It returns True if a number is even, and False if it is odd.

You need to create a while loop outside of the function, and call even_odd to test your random integers.

Instead of giving the answer, here is a guide on how to set up your code. I think you'll be able to solve it from here.

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    #Code goes here

    start -= 1

To answer your question about the start variable, each time the while loop runs, start will decrement by 1. Evenutally, it will equal 0 and the while condition will evaluate to False, which will end the loop.

Hopefully this gets you started. If you still need more help let me know.

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natalie fairbourne

natalie fairbourne

I need help with challenge 3 of 3

1 Answer

Ryan S

Ryan S