Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Number Game App Squared

Posted by Yamil Pérez
Yamil Pérez
Courses Plus Student 2,054 Points

i need help

i dont know what wrong with my code

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
    if num == int(num):
        return num ** 2
    else:
        return (num * len(num))

2 Answers

Stuart Wright
Stuart Wright
41,120 Points
Stuart Wright
Stuart Wright
41,120 Points

You need to use try/except for this challenge rather than if/else. The trouble with your solution is that if your argument cannot be converted to an integer, it just causes an error, and the else block never gets executed. Here's a template for what your code should look like, I'll leave you to fill in the details:

def squared(num):
    try:
        # Convert num to integer, square it, return.
    except:
        # Return num multiplied by its length
Yamil Pérez
PLUS
Yamil Pérez
Courses Plus Student 2,054 Points
Yamil Pérez
Yamil Pérez
Courses Plus Student 2,054 Points

Thank you . your answer was so clear.