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Start your free trialSuleiman Abdurozikov
2,943 PointsI need a help
heeelp
def loopy(items):
for item in items:
print(item)
while True:
if item[0]== "a":
continue
else:
2 Answers
Alexander Davison
65,469 PointsTry this:
def loopy(items):
for item in items:
if item[0] == "a":
continue
else:
print(item)
Good luck! ~alex
Jacob Herrington
15,835 PointsYou are very close, however you've got an extra loop in there.
The "while" loop is unnecessary, you've got a "for ... in" loop to do the work here.
So if you remove the while loop, then think about your If/Else statement. We need the loop to skip something IF a certain value is one of the elements it finds, ELSE we need to print the value of the element we are on. Try it on your own without looking at my code, but if you can't, here is passing code. Try to figure out why this code passes and yours doesn't:
def loopy(items):
for item in items:
if item[0]== "a":
continue
else:
print(item)