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Java Java Basics Perfecting the Prototype Looping until the value passes

eric schwartz
eric schwartz
4,242 Points

I keeping getting a syntax error on this line: console.printf("Because you said " . response . ",you passed the test");

but, I can't see why.

Example.java
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do{
  response = console.readLine("Do you understand while looops");
}while(response.equalsIgnoreCase("no"));
console.printf("Because you said " . response . ",you passed the test");

2 Answers

Chase Marchione
Chase Marchione
155,055 Points

Hi Eric,

Since the answer needs to be a formatted string, one might use %s as the placeholder for our string variable, and pass in the response variable as the second argument to the printf method (which is the print method that is specifically used for formatted strings.)

console.printf("Because you said %s you passed the test!", response);

It's also helpful to enter the strings exactly as challenges suggest. For example, the string we type up on line 4 that is passed to the console.readLine method should be "Do you understand do while loops?".

Hope this helps!