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Start your free trialAndrew Joseph
985 PointsI have no clue what i'm doing wrong
You're doing great! Just one more task but it's a bigger one. Right now, we turn everything into a float. That's great so long as we're getting numbers or numbers as a string. We should handle cases where we get a non-number, though. Add a try block before where you turn your arguments into floats. Then add an except to catch the possible ValueError. Inside the except block, return None. If you're following the structure from the videos, add an else: for your final return of the added floats.
^ is the question.
however, I have no idea what is happening, or what's wrong with my code, as i'm only getting a "Try again!" message.
Help with my code would be well appreciated. thanks.
def add(x, y):
try:
x = int(input("number 1"))
y = int(input("number 2"))
except ValueError:
print("That isn't number")
return None
else:
return(x)
return(y)
a = float(x)
b = float(y)
print (a + b)
2 Answers
Anish Walawalkar
8,534 PointsJust a few pointers:
- In your function add(x, y) you are being passed values for x and y, hence you don't need to input them
- In your try block you need to covert x and y into floats by using float() function, add them up and return the result
- If x or y cannot be converted to floats, python will throw a ValueError exception at which point it will enter the except block where you need to return None
in code it looks like this:
def add(x, y):
try:
return float(x) + float(y)
except ValueError:
return None
Hope that helps
Josh Keenan
20,315 PointsHi Andrew, here's my solution, apologies for the poor formatting!
def add(num1, num2): try: return float(num1) + float(num2) except ValueError: return None else: return num1 + num2
santhosh gattu
551 PointsThanks