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Start your free trialDarius Champion
UX Design Techdegree Student 1,192 Pointsi guess i am just too dumb for this ...
I just can't seem to get this to work ...=( i don't think I am smart enough to get this right .. i can't seem to think logically enough for this but i want to try . can someone tell me what i am doing wrong with this code??
NSArray *drinks=@[@"juice",@"water",@"coffee"];
for (NSObject *loopDrinks in drinks){
NSLog (@%@);
}
2 Answers
Damien Watson
27,419 PointsHi Darius,
You got really close to answering this correctly, you're not that far wrong.
When you output the drink, it is a string not object and printing it you just need to wrap it correctly. I also renamed your variable to 'drink
' as it is each 'drink
' inside 'drinks
':
NSArray *drinks=@[@"juice",@"water",@"coffee"];
for (NSString *drink in drinks){
NSLog(@"%@",drink);
}
Darius Champion
UX Design Techdegree Student 1,192 PointsThanks a lot !!!!
Damien Watson
27,419 PointsCool, feel free to mark it as the correct answer as it may help others. ;)