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Python Python Basics (2015) Letter Game App Exiting

Arthur Berg
Arthur Berg
11,350 Points
Posted by Arthur Berg
Arthur Berg
11,350 Points

I feel that this code challenge has a very unclear mission. This is how I understood the challenge

I can't see what's wrong in the code, I'm doing exactly what they are asking for. I get an error Didn't get an exit for start_movie . I don't even know what they mean with start_movie, is it a variable, a function? They don't say. Very unclear for me.

Help please!

Thanks

firedoor.py 
import sys
start = input("Do you want to start the movie? ")

if start != "n" or "N":
  print("Enjoy the show!")
else:
  sys.exit()

2 Answers

tobiaskrause
tobiaskrause
9,160 Points
tobiaskrause
tobiaskrause
9,160 Points

You almost had it :)

import sys
start = input("Do you want to start the movie? ")

if start.lower() != "n":
  print("Enjoy the show!")
else:
  sys.exit()

This also works:

import sys
start = input("Do you want to start the movie? ")

if not (start == "n" or start == "N"):
  print("Enjoy the show!")
else:
  sys.exit()
Arthur Berg
Arthur Berg
11,350 Points
Arthur Berg
Arthur Berg
11,350 Points

Thanks, waaah learning a new language from scratch is haaaard :P