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Start your free trialChristopher Nelson
5,844 PointsI dont understand why it does not pass
I solved this problem two different ways that I believe are valid, but the system says that they are both incorrect. The for loop prints exactly the output onto the screen and fails.
<?php
//edit this array
$contacts = array(
array(
"name" => "Alena Holligan",
"email" => "alena.holligan@teamtreehouse.com"
),
array(
"name" => "Dave McFarland",
"email" => "dave.mcfarland@teamtreehouse.com"
),
array(
"name" => "Treasure Porth",
"email" => "treasure.porth@teamtreehouse.com"
),
array(
"name" => "Andrew Chalkley",
"email" => "andrew.chalkley@teamtreehouse.com"
)
);
// THE INSTRUCTIONS ASK FOR YOU TO REPLACE THE HARD CODED VALUES WITH THE ARRAY VALUES.
//I DID THIS WITH A FOREACH LOOP AND IT PRINTS TO THE SCREEN CORRECTLY BUT I GET AN ERROR ANYWAY
echo "<ul>\n";
foreach($contacts as $item){
echo "<li>" . $item['name'] . " : " . $item['email'] . "</li>";
};
echo "</ul>\n";
//SO THEN I TRIED TO JUST REPLACE THE HARD CODED NAMES AND EMAILS WITHOUT USING A LOOP, BUT THAT DOES NOT WORK EITHER.
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>"$contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>";
echo "<li>"$contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>";
echo "<li>"$contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>";
echo "<li>"$contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>";
echo "</ul>\n";
1 Answer
Steven Parker
231,198 PointsClose! But each line is missing a concatenation operator and a newline symbol:
<?php
//...
echo "<li>"$contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>"; // original
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n"; // fixed