I don't understand the question really...

Question

I suppose I don't understand the question. I thought I was following the directions.

even.py

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    start = 5

    while true:
        random_int = int(random.randint(1,99))

        if random_int % 2 == 0:
            print("{} is even".format(random_int))
        else:
            print("{} is odd".format(random_int))

        start -= 1
        return not num % 2

Answer 1 · 2016-12-15T05:03:01Z

December 15, 2016 5:03am

when start gets to 0 it will be false
you can leave the even odd function just like it is
your solution works if you make True false at the end point
True needs to be capitalized if you use it
your solution passes w/o the even odd function
I think your indents were off
yes this challenge can be a bit confusing

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start: # Make a while loop that runs until start is falsey
    num = random.randint(1, 99) # Inside the loop, use random.randint(1, 99)
    if even_odd(num): # If that random number is even (use even_odd to find out)
        print("{} is even".format(num)) # putting the random number in the hole
    else: # Otherwise
        print("{} is odd".format(num)) # again using the random number
    start -= 1 # Finally, decrement start by 1

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I don't understand the question really...

1 Answer

john larson

john larson