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Start your free trialeduvanta
7,425 PointsI don't understand the correction statement. To display this in PHP, is my associative array to be called or imploded?
When I call the array, the PHP converter says error, and that it should be converted to a string (as I expect). So in order to convert it to a string, I implode the array to display it.
The output seems to match what is required. However when I implode it, I get a correction statement saying it doesn't see the correct output and that the array should just be called. I've tried different ways but I seem to get conflicting statements between the PHP converter and the correction statement.
I'm feel I understand arrays pretty well, but I can't seem to get past this lesson. I'm new to this, so there could be something I'm overlooking or overthinking. Please help.
- Don
<?php
//edit this array
//$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
$contacts[] = array('name' => 'Alena Holligan', 'email' => 'alena.holligan@teamtreehouse.com');
$contacts[] = array('name' => 'Dave McFarland', 'email' => 'dave.mcfarland@teamtreehouse.com');
$contacts[] = array('name' => 'Treasure Porth', 'email' => 'treasure.porth@teamtreehouse.com');
$contacts[] = array('name' => 'Andrew Chalkley', 'email' => 'andrew.chalkley@teamtreehouse.com');
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
$contact1 = implode(" : ", $contacts[0]);
$contact2 = implode(" : ", $contacts[1]);
$contact3 = implode(" : ", $contacts[2]);
$contact4 = implode(" : ", $contacts[3]);
echo "<li>$contact1</li>\n";
echo "<li>$contact2</li>\n";
echo "<li>$contact3</li>\n";
echo "<li>$contact4</li>\n";
1 Answer
Umesh Ravji
42,386 PointsHey Don, the question is this case specifically wants you to access the array elements to generate the output (use $contacts[index]['name'] and $contacts[index]['email'].