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Java Java Basics Getting Started with Java IO

Rampant Developer
Rampant Developer
2,784 Points
Posted by Rampant Developer
Rampant Developer
2,784 Points

I don't understand how this line is wrong: console.printf("First name: %s", firstName);

the code checker keeps asking if I forgot to pass the firstName to the printf function, which I haven't. I don't know how to solve this code challenge.

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = "";
String lastName = "";
console.readLine(firstName);
console.readLine(lastName);
console.printf("First name: %s", firstName);

2 Answers

Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points
Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points

Hi :) That's the correct answer :

String firstName = "";
String lastName = "";
firstName = console.readLine();
lastName = console.readLine();
console.printf("First name: %s", firstName);

and that's why : you have a String but is empty so you must get a value from the user ... at console.readLine( "here goes the message for user ... example : enter your name " );

so the line isn't wrong but the value of String firstName it's null and this is wrong

with tis way :

firstName = console.readLine();

you pass at this string the value that user write

check out again the last video :)

Rampant Developer
Rampant Developer
2,784 Points
Rampant Developer
Rampant Developer
2,784 Points

that did the trick. Thank you very much for the help!