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iOS Functions in Swift Adding Power to Functions Function Parameters

Nigel Matheson
PLUS
Nigel Matheson
Courses Plus Student 1,166 Points

I don't know why this is not working

I believe I had got this right but it still doesn't work?

Help!

functions.swift
// Enter your code below
func getRemainder (value a: 10, divisor b: 3) -> Int { return a % b}


let result = getRemainder (value: 10, divisor: 3) 

2 Answers

Jeff McDivitt
Jeff McDivitt
23,970 Points

In your function the values are of type Int. You do not input numbers until you call the function

func getRemainder(value a: Int, divisor b: Int) -> Int {

return a % b

}