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Siddesh Gannu
3,565 Pointsi dont know where to start Help
I Dont know where to start. I'm just confused what to do. I know the topics and everything but I can't seem to figure out how to move forward with this. Please help. thanks
public class Example {
public static void main(String[] args) {
ShoppingCart cart = new ShoppingCart();
Product pez = new Product("Cherry PEZ refill (12 pieces)");
cart.addItem(pez, 5);
/* Since a quantity of 1 is such a common argument when adding a product to the cart,
* your fellow developers have asked you to make the following code work, as well as keeping
* the ability to add a product and a quantity.
*/
Product dispenser = new Product("Yoda PEZ dispenser");
cart.addItem(dispenser);
}
}
public class ShoppingCart {
public void addItem(Product item, int quantity) {
System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
/* Other code omitted for clarity. Please imagine
lots and lots of code here. Don't repeat it.
*/
}
}
public class Product {
/* Other code omitted for clarity, but you could imagine
it would store price, options like size and color
*/
private String mName;
public Product(String name) {
mName = name;
}
public String getName() {
return mName;
}
}
1 Answer
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 PointsHey Siddesh,
What this challenge is asking us to do is to create a new method that only requires the argument of a Product, and in the body of our new method to eliminate the mistake of repeating ourselves, we'll call the already supplied method, passing in the item, and the value of 1, it would look like below:
public class ShoppingCart {
public void addItem(Product item, int quantity) {
System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
/* Other code omitted for clarity. Please imagine
lots and lots of code here. Don't repeat it.
*/
}
public void addItem(Product item) {
addItem(item, 1);
}
}