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Start your free trialLuis Aguilar
750 PointsI don't know where to go after making the function 'even_odd'
This one should be short and sweet.
Write a function named even_odd that takes a single argument, a number.
return True if the number is even, or False if the number is odd.
You can use % 2 to find out the remainder when dividing a number by 2. Even numbers won't have a remainder....
2 Answers
Christophe Pouliot
6,495 PointsIf you want to make a short one you can do
def even_odd(num):
return False if num % 2 else True
If the number is not a multiple of 2 the value of num % 2 will be 0, which is "Falsy".
Otherwise, return True if the value of num % 2 is not 0 (Which is "Truthy").
What you could also do is
def even_odd(num):
return not bool(num % 2)
This casts the value of num % 2 to a boolean, which will be False if the value is 0 and True if the value is other than 0 (Which means there is a remainder). You then take the opposite (the not) because the answer will be True if there is a remainder, and you want the answer to be True if the number is even (no remainder).
Carlos Federico Puebla Larregle
21,074 PointsI can't see your code but you can solve it like this:
def even_odd(num_arg):
if num_arg % 2 == 0:
return True
else:
return False
I hope that helps a little bit