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Start your free trialHubert Rzymski
986 PointsI don't know what is wrong with this solution, it's working on Xcode.
Everything is on subject, I don't know what's is wrong.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
switch n
{
case n where n % 3 == 0 && n % 5 == 0: return "FizzBuzz"
case n where n % 3 == 0: return "Fizz"
case n where n % 5 == 0: return "Buzz"
}
// End code
return "\(n)"
}
2 Answers
Jhoan Arango
14,575 PointsHello Hubert,
I am sorry for the late response.
Your code is excellent, and it works perfect.. The only thing is that you have to remember that switching always has to be exhaustive. In this case, since it can not be, then we have to add a default. This means that after the evaluation of all the cases you gave, it will end execution.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
switch n
{
case n where n % 3 == 0 && n % 5 == 0: return "FizzBuzz"
case n where n % 3 == 0: return "Fizz"
case n where n % 5 == 0: return "Buzz"
default: break // Adding a break, this will stop the execution
}
// End code
return "\(n)"
}
Hope this help
Hubert Rzymski
986 PointsThanks very much, I solved this by deleting switch and using if, btw really thanks you.