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Start your free trialSohaib Rashid
627 PointsI don't know what is wrong here, i get an error mesasage of bad operand type String for unary operator '!'
I know what the error is, i don't know to fix it
public class TeacherAssistant {
public static String validatedFieldName(String fieldName) {
// These things should be verified:
// 1. Member fields must start with an 'm'
// 2. The second letter in the field name must be uppercased to ensure camel-casing
// NOTE: To check if something is not equal use the != symbol. eg: 3 != 4
if(!fieldName) {
throw new IllegalArgumentException();
}
return fieldName;
}
}
1 Answer
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 PointsHello, I think I answered your other question, but just incase. Try the following code below.
public class TeacherAssistant {
public static String validatedFieldName(String fieldName) {
// These things should be verified:
if (fieldName.charAt(0) != 'm' || !Character.isUpperCase(fieldName.charAt(1)) ) {
throw new IllegalArgumentException("Illegal field name");
}
// 2. The second letter in the field name must be uppercased to ensure camel-casing
// NOTE: To check if something is not equal use the != symbol. eg: 3 != 4
return fieldName;
}
}
You are first checking to make sure that the char 'm' is the first char in the string, then you are checking to make sure that the second is capitalized. If either of these conditions are not met than you are throwing the exception.
Thanks, let me know if this helps!
Sohaib Rashid
627 Pointsahh you made it so much easier to understand! you have definitely helped! thank you and happy coding!
Dovev Golan
425 PointsDovev Golan
425 PointsHey,
The "!" operator is for boolean variants.
Try this :
If (fieldName == null) .....