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C# C# Objects Inheritance Catching Exceptions

FEI LI
FEI LI
828 Points

I don't know how to write inside the "try" block

and what's the logic? Do I have to throw an exception before I use try and catch?

Program.cs
int value = int.Parse(Console.ReadLine());

if (value < 0 || value > 20)
{
    throw new System.Exception();

}
try{
    value ;
   }
catch(Exception)
{
    Console.WriteLine("value is out of bounds!");
}


Console.WriteLine(string.Format("You entered {0}",value));

1 Answer

Chris Jones
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points

Hey FEI,

In order to catch the exception, it needs to be thrown inside the TRY block. So, you'll need to wrap the existing code in a TRY-CATCH block like so:

int value = int.Parse(Console.ReadLine());

try
{
    if (value < 0 || value > 20)
    {
        throw new System.Exception();
    }
    Console.WriteLine(string.Format("You entered {0}",value));
}
catch (Exception)
{
    Console.WriteLine("Value is out of bounds!");
}

If the IF statement returns true, then an exception is thrown. Then exception is caught in the CATCH block and "Value is out of bounds!" is written to the console.

Let me know if you have any more questions!