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Start your free trialLee Finch
Courses Plus Student 1,411 PointsI dont know how to do this
Im either getting an array needed but string found error when i use the index, or i get a bad use of symbol error when i do not use index
public class ConferenceRegistrationAssistant {
public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
int line = 0;
if(lastName[0] <= "M")
{
line = 1;
}
else
line = 2;
return line;
}
}
2 Answers
Alistair Mackay
7,812 PointsYou're close but as Daniel pointed out above you're not checking the first letter of lastName correctly - change your quotes to single quotes and make use of the charAt() method to get the first letter of the lastName variable.
The below code worked for me, give it a try if you're really stuck:
public class ConferenceRegistrationAssistant {
public int getLineFor(String lastName) {
/* If the last name is between A
thru M send them to line 1, otherwise
send them to line 2 */
int line = 0;
/* if the first char of lastName Less
than/equal too 'A' && Greater than/
equal too 'M' return line = 1; else line 2;*/
if (lastName.charAt(0) >= 'A' && lastName.charAt(0) <= 'M') {
line = 1;
} else {
line = 2;
}
return line;
}
}
I hope the above helps.
daniel104729
7,176 PointsIn Java strings are not character arrays. If you want to get a particular character from a String you call the charAt(int index) function. You see more details about Java String by looking at the docs provided by Oracle https://docs.oracle.com/javase/8/docs/api/java/lang/String.html. You may need to surround the M with single quotes so it will be evaluated as a char instead of a String.