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Java Java Basics Perfecting the Prototype Parsing Integers

Posted by Stephen Williams
Stephen Williams
4,419 Points

I do not understand what i did wrong

Please help! XD

ParsingInts.java 
String answerToLife = "42";
int answer = Integer.parseint(answerToLife);

2 Answers

Jamie Kilburn
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.a{fill-rule:evenodd;}techdegree
Jamie Kilburn
iOS Development Techdegree Student 6,802 Points
Jamie Kilburn
.a{fill-rule:evenodd;}techdegree
Jamie Kilburn
iOS Development Techdegree Student 6,802 Points 
String answerToLife = "42";
int answer = Integer.parseInt(answerToLife);

Is the correct code, you used parseint() instead of parseInt().

simon k
simon k
592 Points
simon k
simon k
592 Points

I'm getting an error "java.lang.NumberFormatException: For input string: "answerToLife" ()"

String answerToLife = "42";
int answer = Integer.parseInt("answerToLife");
Jamie Kilburn
seal-mask
.a{fill-rule:evenodd;}techdegree
Jamie Kilburn
iOS Development Techdegree Student 6,802 Points
Jamie Kilburn
.a{fill-rule:evenodd;}techdegree
Jamie Kilburn
iOS Development Techdegree Student 6,802 Points

You're trying to pass in a String that is equal to "answerToLife", you have to remove the quotes around what you used. Right now the compiler is trying to parse "answerToLife" for a number, and it can't find one. Use what I wrote in the previous response, it's the correct way to do this question.