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Start your free trialEZE IKE
3,671 PointsI do not see the use of the names from contacts array in the output. When calling the multidimensional array, you must f
I do not see the use of the names from contacts array in the output. When calling the multidimensional array, you must first call the outer indexed array and then the inner associative array. Example: $array[#][STRING]
<?php
//edit this array
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
$contacts = array (
array (
'name' => 'Alena Holligan',
'email' => 'alena.holligan@teamtreehouse.com',
),
array (
'name' => 'Dave McFarland',
'email' => 'dave.mcfarland@teamtreehouse.com',
),
array (
'name' => 'Treasure Porth',
'email' => 'treasure.porth@teamtreehouse.com',
),
array (
'name' => 'Andrew Chalkley',
'email' => 'andrew.chalkley@teamtreehouse.com',
),
);
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>". $contacts [0]["name"] . " : " . $contacts [0]["email"] . "</li>\n";
echo "<li>". $contacts [1]['name'] . " : " . $contacts [1]['email'] . "</li>\n";
echo "<li>". $contacts [2]['name'] . " : " . $contacts [2]['email'] . "</li>\n";
echo "<li>". $contacts [3]['name'] . " : " . $contacts [3]['email'] . "</li>\n";
echo "</ul>\n";
?>
2 Answers
Algirdas Lalys
9,389 PointsHi EZE,
What I have noticed, that first is duplicating you don't need it
echo "<ul>\n";
and first array is not nessesery you can delete it too.
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
And second when you are echoing for example $contacts [0]["name"], there should't be any spaces between $contacts and [0]["name"]. So the right way should be something like that.
echo "<ul>\n";
echo "<li>". $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
echo "<li>". $contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>\n";
echo "<li>". $contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>\n";
echo "<li>". $contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>\n";
echo "</ul>\n";
I hope it helps:)
Algirdas Lalys
9,389 PointsHmm, then I guees you can try final code it should work. It works for me.
<?php
$contacts = array (
array (
'name' => 'Alena Holligan',
'email' => 'alena.holligan@teamtreehouse.com',
),
array (
'name' => 'Dave McFarland',
'email' => 'dave.mcfarland@teamtreehouse.com',
),
array (
'name' => 'Treasure Porth',
'email' => 'treasure.porth@teamtreehouse.com',
),
array (
'name' => 'Andrew Chalkley',
'email' => 'andrew.chalkley@teamtreehouse.com',
),
);
echo "<ul>\n";
echo "<li>". $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
echo "<li>". $contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>\n";
echo "<li>". $contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>\n";
echo "<li>". $contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>\n";
echo "</ul>\n";
?>
EZE IKE
3,671 PointsEZE IKE
3,671 Pointshi thanks for response.but it still says " I do not see the use of the names from contacts array in the output"