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572 Pointsi couldn't find answer
i couldn't find the answer
def loopy(items):
items=input("> ")
if items.index(0)=="a"
continue
print(items)
# Code goes here
1 Answer
Chris Jones
Java Web Development Techdegree Graduate 23,933 PointsHi Yusuf,
Good try! A couple things to consider:
First, items
is the function's parameter, so someone will provide items
for the function when calling your loopy
function. So, you don't need to change the items
parameter with this line:
items=input("> ")
I know this can be a difficult concept to understand because it requires you to think outside of the code you're writing and how your code will be used by others. Stick with it - you'll get it :)!
Second, if you create a for
loop, you need to finish the line with a colon (:), so this line:
if items.index(0)=="a"
needs to be:
if items.index(0)=="a": # notice the colon at the end of the line.
The code challenge tells you that the items
parameter will be list of strings(["abc", "xyz"]), so we want to loop through each of the list items, like so:
def loopy(items):
for item in items:
if item[0] != 'a':
print(item)
Notice that there is also no index
method for a string. If the first character in a string is needed, write item[0]
.
I hope this helps! Let me know if you have any more questions! Keep it up :)!!