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iOS Functions in Swift Adding Power to Functions Returning Complex Values

Jose Vaides
Jose Vaides
18,136 Points
Posted by Jose Vaides
Jose Vaides
18,136 Points

I can't use "for" as a name for the external variable, since this is a reserved word for loops in Swift

It's not possible to use "for" as a name for the external variable, since this is a reserved word for swift. Is there something I'm doing wrong? the code works when I change "for" for another name for the variable.

functions.swift 
// Enter your code below
func coordinates(for: String)->(Double, Double){
    let location=for

    switch location{
    case "Eiffel Tower": return(48.8582,2.2945)
    case "Great Pyramid": return(29.9792,31.1344)
    case "Sydney Opera House": return(33.8587,151.2140)
    default: return(0,0)
    }
}

1 Answer

n8
n8
13,047 Points
n8
n8
13,047 Points

Add a space and the word location. You also don't need the location constant.

It should read: func coordinates(for location: String) -> (Double,Double) {}

Jose Vaides
Jose Vaides
18,136 Points
Jose Vaides
Jose Vaides
18,136 Points

Thanks a lot, that fixed it!