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Start your free trialAbhilasha jangid
2,925 Pointsi can't understand q
where i add throw & why ... what mean of illegalArgumentException iae i don't understand it clealy....
class GoKart {
public static final int MAX_BARS = 8;
private String color;
private int barCount;
private int lapsDriven;
public GoKart(String color) {
this.color = color;
}
public String getColor() {
return color;
}
public void charge() {
barCount = MAX_BARS;
}
public boolean isBatteryEmpty() {
return barCount == 0;
}
public boolean isFullyCharged() {
return MAX_BARS == barCount;
}
public void drive() {
drive(1);
}
public void drive(int laps) {
lapsDriven += laps;
barCount -= laps;
if(lapsDriven > laps){
throw new IllegalArgumentException iae("");
}
}
}
2 Answers
Simon Coates
28,694 Pointsmy guess is:
public void drive(int laps) {
if( laps>barCount){//changed
throw new IllegalArgumentException("");//changed
}
//only change if legal to do so
lapsDriven += laps;
barCount -= laps;
}
Pranjal Agnihotri
4,187 PointsHii Abhilasha , IllegalArgumentException is a class in Java in short we call it iae. In this case(GoCart.java) you have added throw correctly. When the lapdriven will be greater than the maximum laps then it will be exception as lapdriven cannot be greater than the maximum laps. So thats why we are throwing that exception that it is Illegal. Hope it helps!.