Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Trushit Patel
Trushit Patel
477 Points

I can't make out my mistake -

Please help me with this. I don't see any error in this.

Name.java
String firstName = "Trushit" ;
console.printf("%s",firstName);// I have setup a java.io.Console object for you named console

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points

The problem is you're not printing what the instruction is asking you:

// I have setup a java.io.Console object for you named console
String firstName = "Trushit";
console.printf("%s can code in Java!", firstName);

Hi Trushit,

you just made a small mistake in your code: There is space between "Trushit" and the semicolon. Just delete the space and the program will run :)

String firstName = "Trushit";
console.printf("%s",firstName); 

I hope that was helpful, Patrick