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Python Python Basics (2015) Letter Game App Even or Odd Loop

Pii Tiimii
Pii Tiimii
3,036 Points
Posted by Pii Tiimii
Pii Tiimii
3,036 Points

I cant get pass this challenge

import random start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2

while start: a = random.randint(1, 99)

if even_odd(a):
  print("{} is even".format(str(a)))
else:
  print("{} is odd".format(str(a)))
start-=1

It says Wrong number of prints.

even.py 
import random
start = 5
def even_odd(num):
  # If % 2 is 0, the number is even.
  # Since 0 is falsey, we have to invert it with not.
  return not num % 2

while start == True:
  a = random.randint(1, 99)
  b = str(a)
  if even_odd(a) == 1:
    print("{} is even".format(b))
  if even_odd(a) == 0:
    print("{} is odd".format(b))
  start-=1

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Since start is initially 5, the while condition will be false since 5 is not equivalent to True. You can use the " truthiness" of start instead as while start:

Also, since even_odd() returns a Boolean value, the return value can be used directly as the if condition without comparing to 1 or 0.

You don't have to creat b for use in the format method. a can be used directly. Format will convert to str for you.