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Start your free trialRamon Berke
637 PointsI am stuck in this task can somebody tell me my mistake?
The task says "My loopy function needs to skip an item this time, though.Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".". I wrote this but the bummer says "name 'item' is not defined.".Can somebody tell me my mistake? (and can you send the code because its easier for me to understand.)
def loopy(items):
# Code goes here
while True:
print(item)
if item.index(0) == 'a':
continue
else:
print(item)
1 Answer
Reyam Marcos
Courses Plus Student 10,367 Pointsyou dont need a while loop for this one, check this one
def loopy(items):
# Code goes here
for item in items:
if item[0] == "a":
continue
print(item)
hope it helps
Ramon Berke
637 PointsRamon Berke
637 PointsThank you so much. It workedd.