I am stuck for longer than I like to admit on the getTileCount() function

Question

I don't even know where to start. Could someone just tell me what is wrong?

One of the biggest issues right now is, that I don't know how to use the tile variable in the for-each loop, which I already declared in the function arguments?

ScrabblePlayer.java

public class ScrabblePlayer {
  private String mHand;

  public ScrabblePlayer() {
    mHand = "";
  }

  public String getHand() {
   return mHand;
  }

  public int getTileCount(char tile){
  int tileCount;
  char[] mHandArray = mHand.toCharArray();
  for( tile : mHandArray ){
   tileCount += 1;
  }
  return tileCount;
  }

  public void addTile(char tile) {
    // Adds the tile to the hand of the player
    mHand += tile;
  }

  public boolean hasTile(char tile) {
   return mHand.indexOf(tile) > -1;
  }
}

Answer 1 · 2016-01-12T17:04:07Z

January 12, 2016 5:04pm

So you have to make a function that takes a char/letter as input and that returns an integer equal to the number of times that the player has the given char in his hand. So you start by creating a count variable and setting it to 0. Then u use the 'for each' loop. So to be able to look for letters in the String mHand we first convert it to an array of chars using the '.toCharArray'. Then the 'for each' loop will run for each char in the array. In the loop you have to put an if statement to check if char that is giving in the function is equal to the char in the array. If it's the same letter then you increment the counter by 1. Finally you just return the count variable.

public int getTileCount(char letter) {
    int count = 0;
    for (char tile : mHand.toCharArray()) {
      if (letter == tile) {
        count += 1;
      }
    }
    return count;
  }

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Yassin Sassi

Yassin Sassi

I am stuck for longer than I like to admit on the getTileCount() function

1 Answer

Lee Geertsen

Lee Geertsen