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648 PointsI am so sorry, I tried several times but my answer turns out "Bummer!" What does this task ask me to do?
I am so sorry, I tried several times but my answer turns out "Bummer!" What does this task ask me to do? I made this string, "string firstName = "Min"; I am sure that this work is correct. I don't know what 'a compiler error' means. What do I need to add ? I appreciate it.
// I have setup a java.io.Console object for you named consoles
string firstName = "Min" ;
2 Answers
Loris D'Antonio
Courses Plus Student 10,155 PointsHello Min,
Pay attention to the variable type you are declaring, its case sensitive.
In fact, string does not exist, String does
String firstName = "Min" ;
Min ..
648 PointsOh I see. But one more question. When I type "console.printf" , It didn't matter if I started with lowercase. But in case of "String", does it matter? Because string does not exist? Is it explained just like that? Thanks in advance!
Loris D'Antonio
Courses Plus Student 10,155 PointsWhen I type "console.printf" , It didn't matter if I started with lowercase
it matters, depends how you have declared your console object, remember that is java is case sensitive.
The following code will work:
Console console; //declaration, your Console object is named console
console = System.console(); //definition
console.printf("Hello !");
Console (upper case C) - is the class
console - is the name you are giving to your object.
so, to use properly your object, the syntax is:
<object_name>.<method>
console.printf()
this instead, will not work:
Console objConsole; //declaration
objConsole = System.console(); //definition
objconsole.printf("Hello !"); // ERROR: we are trying to use objconsole, but does not exist ! (c should be UpperCase)
Min ..
648 PointsYou are so perfect