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Start your free trialMatthew Clark
7,255 PointsI am not sure what the code should look like for this, and why it is that way?
var listItems = navigation.querySelector("input[type=li]");
Above is my code, and it is attached.
//Select the naviagation
var navigation = document.getElementById("navigation");
//Select all listItems from the navigation
var listItems = navigation.querySelector("input[type=li]");
//When a navigation link is pressed
var linkListener = function() {
console.log("Listener is clicked!");
}
var bindEventsToLinks = function(listItem) {
//Select the anchor
var anchor = listItem;
//Bind the linkListener to the anchor element (a)
anchor.onclick = linkListener;
}
for(var i = 0; i < listItems.length ; i++) {
bindEventsToLinks(listItems[i]);
}
<!DOCTYPE html>
<html>
<head></head>
<body>
<ul id="navigation">
<li>
<a href="#home">Home</a>
</li>
<li>
<a href="#about">About</a>
</li>
<li>
<a href="#contact">Contact</a>
</li>
</ul>
<p>A few of my favourite things:</p>
<ul>
<li>
Rain drops on roses
</li>
<li>
Whiskers on kittens
</li>
<li>
Brown paper packages wrapped up with string
</li>
</ul>
<script src="app.js"></script>
</body>
</html>
1 Answer
Mohammed Khalil Ait Brahim
9,539 PointsIf you use query selector, you are able to select element as if you were using css so to get a list item you only need to put li. But again this is not what is asked by the task you need to select all list items and querySelector returns the first match only. To select all children of an element you use children property
var listItems = navigation.children;