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Java Java Basics Perfecting the Prototype String Equality

Matthew Maslow
Matthew Maslow
454 Points
Posted by Matthew Maslow
Matthew Maslow
454 Points

I am having trouble figuring out the ignorecase if statement condition

It keeps saying there is a syntax error and I cannot figure out why

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample){
  console.printf("first is equal to second");
}
if (thirdExample.equalsIgnoringCase("hello")){
  console.printf("first and third are the same ignoring case");
}

1 Answer

Jason Larson
Jason Larson
8,359 Points
Jason Larson
Jason Larson
8,359 Points

The method is equalsIgnoreCase(). You have equalsIgnoringCase(). Try this:

if (thirdExample.equalsIgnoreCase("hello")){
  console.printf("first and third are the same ignoring case");
}