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Start your free trialZahra Aljuboori
619 PointsI am having problemes with starting this task
Can I add new variables to the code, and should take inspiration from the code in game class?
public class ConferenceRegistrationAssistant {
/**
* Assists in guiding people to the proper line based on their last name.
*
* @param lastName The person's last name
* @return The line number based on the first letter of lastName
*/
public int getLineNumberFor(String lastName) {
int lineNumber = 0;
int whichLine = lastname.indexOf(0);
if (whichLine) {
lastname
/*
lineNumber should be set based on the first character of the person's last name
Line 1 - A thru M
Line 2 - N thru Z
*/
return lineNumber;
}
}
public class Example {
public static void main(String[] args) {
/*
IMPORTANT: You can compare characters using <, >. <=, >= and == just like numbers
*/
if ('C' < 'D') {
System.out.println("C comes before D");
}
if ('B' > 'A') {
System.out.println("B comes after A");
}
if ('E' >= 'E') {
System.out.println("E is equal to or comes after E");
}
// This code is here for demonstration purposes only...
ConferenceRegistrationAssistant assistant = new ConferenceRegistrationAssistant();
/*
Remember that there are 2 lines.
Line #1 is for A-M
Line #2 is for N-Z
*/
int lineNumber = 0;
/*
This should set lineNumber to 2 because
The last name is Zimmerman which starts with a Z.
Therefore it is between N-Z
*/
lineNumber = assistant.getLineNumberFor("Zimmerman");
/*
This method call should set lineNumber to 1, because 'A' from "Anderson" is between A-M.
*/
lineNumber = assistant.getLineNumberFor("Anderson");
/*
Likewise Charlie Brown's 'B' is between 'A' and 'M', so lineNumber should be set to 1
*/
lineNumber = assistant.getLineNumberFor("Brown");
}
}
2 Answers
Raffael Dettling
32,999 PointsIn the first if statmant you ceck if the firs letter is between A and M with the && operator and the charAt() methode.
if(lastName.charAt(0) >= 'A' && lastName.charAt(0) <= 'M')
Then in the second statment check if the letter is between N and Z
else if(lastName.charAt(0) >= 'N' && lastName.charAt(0) <= 'Z')
In Java you have to use the single quotes to signal that the letters are chars not strings :) you can of course just use an else to return 2
Zahra Aljuboori
619 Pointsthe answer is char result = lastName.charAt(0); if (result<='M'){ lineNumber=1; }else { lineNumber=2; }
Zahra Aljuboori
619 PointsZahra Aljuboori
619 PointsThanx for your fast answer, I did it my selv, my methode is a little bit different then yours.