Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Perfecting the Prototype Looping until the value passes

Maati Grouni
Maati Grouni
2,481 Points

I am having a problem with a do while loop to print out a string with a variable

does any one can tell me how to print out a string with a variable inside do while loop that I'm having trouble with thanks

Example.java
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response = console.readLine("Do you understand do while loops?");

    console.printf("Because you said<response>, you passed the test!");

}while(response.equalsIgnoreCase("No"));

1 Answer

andren
andren
28,558 Points

When printing a string with printf you can place a %s placeholder within the string which will be replaced with a string you pass in as the second argument to the printf method. Like this:

console.printf("Because you said %s, you passed the test!", response);

The challenge wants the message to be printed out after the loop runs though, not within the loop. So you need to place the printf statement below the loop. Like this:

String response;
do {
  response = console.readLine("Do you understand do while loops?");
} while(response.equalsIgnoreCase("No"));

console.printf("Because you said %s, you passed the test!", response);