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Python Solution

fahad lashari
fahad lashari
7,693 Points
Posted by fahad lashari
fahad lashari
7,693 Points

How would one achieve this without the use of the built in min() function?

I'd like to know how someone may achieve this without using the min() function. Much appreciated in advance

2 Answers

Emmanuel Mejia
Emmanuel Mejia
5,886 Points
Emmanuel Mejia
Emmanuel Mejia
5,886 Points

You can also create a very basic function by using sorted and calling the 1st index spot for example i have two functions that accomplish the same thing.

def alph_order(list):
    print(sorted(list)[0])

def alph_order(list):
    new_order = sorted(list)
    print(new_order[0])

The most easy to follow is me sorting the list using "sorted" and assigning it to "new_order" and then return or print the 1st index spot of "new_order"

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The "less than" operator (<) will identify alphabetical order when used on strings. So you could loop through the list, comparing each entry to the previous one, and saving the one that compares "least" in a temporary variable. The "min" value will be in that variable when the loop finishes.