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Start your free trialIdan shami
13,251 Pointshow to solve this challenge? help, please...
please help. I don't understand what I need to do here.... also, can you remind me videos that will help me solve it?
Thanks, Idan.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
if number == num:
return int(num) ** 2
elif string == num:
return string * len(string)
2 Answers
Idan shami
13,251 Pointsit isn't working ^, but thanks for the information
Henry MacAfee
5,077 PointsWhoops! Copied it from another repl that uses two spaces instead of four. Try this:
def squared(num):
if type(num) == int:
num = num ** 2
elif type(num) == str:
num = num * len(num)
return num
Idan shami
13,251 Pointsstill not working XD
Henry MacAfee
5,077 PointsHenry MacAfee
5,077 PointsWhen trying to determine the type of a variable, you must use the type() function. This will return the type, and you can use it in your 'if' statements. Something like this should do the trick: