How to run console.printf in do while loop

Question

How do you make it so that console.printf("Drumroll please.....%n"); run only when the loop is set to increment and gives you an integer greater than one. For example the code runs once and it says "Drumroll please....". But as soon as the number inside the loop gets bigger(lets say 2) the code runs:

"Drumroll please...." "Drumroll please...."

code:

`//Hit a strike int attempts = 0; boolean strike = false;

  do {
    console.printf("Drumroll please....%n");

    strike = luck.nextBoolean();
    attempts++;
  } while(!strike);


  console.printf("You got a strike in %d attempts! %n", attempts);
   System.exit(0);

`

Answer 1 · 2016-08-08T05:09:38Z

August 8, 2016 5:09am

Your question is phrased in a slightly confusing way but if what you are asking if how to have the printf statement only execute, or execute differently based on some condition then the answer, as it often is when you only want to run code in certain conditions, is to use an if statement.

   //Hit a strike 
   int attempts = 0; 
   boolean strike = false;

 do {
    if (attempts == 0) {
    console.printf("Drumroll please....%n");
    } 
    else {
    console.printf("Drumroll please.... Drumroll please....");
    }

    strike = luck.nextBoolean();
    attempts++;
 } while(!strike);

 console.printf("You got a strike in %d attempts! %n", attempts);
 System.exit(0);

That code would achieve what you describe, "Drumroll please....%n" will only be printed the first time though the loop, and "Drumroll please.... Drumroll please...." will be printed all other times through the loop, the if else statement could of course be modified to change this behavior further if you wished.

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Carl Sergile

Carl Sergile

How to run console.printf in do while loop

1 Answer

andren

andren

Carl Sergile

Carl Sergile