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Start your free trialSamantha Keller
7,811 PointsHow is the applyGuess(String) method associated with the applyGuess(char) method?
Hi All!
I am just a little confused as to how both the applyGuess methods are linked together to run properly. I think its mentioned in the video
return applyGuess(letters.charAt(0));
calls the original method but I'm a little confused as to how its associated with our original method since our new method uses 'letters' and the old one uses 'letter' as the variable, unless i have something mistyped, but everything seemed to run fine. Below is my code for that section incase i did just type something up wrong.
Thanks in advance! :)
public boolean applyGuess(String letters){
if(letters.length() == 0){
throw new IllegalArgumentException("No Letter Found");
}
return applyGuess(letters.charAt(0));
}
public boolean applyGuess(char letter){
letter = normalizeGuess(letter);
boolean isHit = answer.indexOf(letter) != -1;
if (isHit) {
hits += letter;
}else{
misses += letter;
}
return isHit;
}
1 Answer
Edvardas Markevicius
Courses Plus Student 9,193 PointsHey! The methods are both booleans, so in the end they return a true or false. So your applyGuess(String letters) method first checks the "if(letters.length() == 0)" statement, if it's true, the method just stops and throws the error. But if it's false it will run your second method applyGuess(char letter) that checks if the letter is a hit or not, then the second method simply returns true or false to the first method. Hope this helps :)
Mladen Jovanovic
4,662 PointsMladen Jovanovic
4,662 PointsWhat I'm wondering, though, is how does our program differentiate between the two "applyGuess" methods, considering that they have the same name and are both booleans.
I do understand that, based on our code, a character will be put into the brackets for the second method, but why wouldn't the program recognize "applyGuess(letters.charAt(0)" as the method that requires a String and give us an error, since it only received a char?