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Start your free trialJamel Stringer
Courses Plus Student 906 PointsHow do I solve breaks.py Challenge 2 of 2
I don't see what I am doing wrong. Here are the details. Keep in mind I was not ask to create any list.
Challenge:Task 2 of 2 Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!
Error Msg: Bummer! Didn't find the right items being printed.
My Code: def loopy(items): for i in items: print(i) if i == "STOP": break
def loopy(items):
for i in items:
print(i)
if i == "STOP":
break
2 Answers
Daniel Schmidt
9,780 PointsTry this:
def loopy(items):
# Code goes here
for item in items:
if item == "STOP":
break
else:
print(item)
Antonio De Rose
20,885 Pointsyou are so close, one thing I would want to emphasis is, if the 1st variable itself to have the value 'STOP', it should break out, without printing, your case it does print, regardless, hence you got to check for the value STOP, and then print it.
Jamel Stringer
Courses Plus Student 906 Points@ Antonio I see the logic. Thank you for your reply.
Jamel Stringer
Courses Plus Student 906 PointsJamel Stringer
Courses Plus Student 906 PointsAfter taking Antonio's advice and seeing your code it makes total sense. Thanks for replying with visuals @ Daniel !