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Python Python Basics (2015) Number Game App Even or Odd

Posted by dima Dima
dima Dima
901 Points

how can I write a function that takes a single arguement which is a number and returns true if the number is even

and false if the number is wrong

even.py 
def even_odd():
    secret_number=random.randit()
    if secret_number % 2 == 0
        print(True)
    else:
        print(False)

2 Answers

Andreas cormack
.a{fill-rule:evenodd;}techdegree seal-36
Andreas cormack
Python Web Development Techdegree Graduate 33,011 Points

Hi Dima

You were very close. You dont need to print true or false, rather return true or false.

See below

def even_odd(num):
    if num % 2 == 0:
        return True
    else:
        return False
dima Dima
dima Dima
901 Points
dima Dima
dima Dima
901 Points

thank you very much, I managed to finish the task