hi guys

Question

def loopy(items):
    # Code goes here
    items=['abz', 'xyz']
     if index[0] in items=='a'
        continue
        else"
        print(item)
```breaks.py
def loopy(items):
    # Code goes here
    items=['abz', 'xyz']
     if index[0] in items=='a'
        continue
        else"
        print(item)
```

FHATUWANI Dondry MUVHANGO · Answer

you need to first loop through each item in "items", its better if you use the "for loop" to do that
and also you need to target the first item and test if it is equal to the string 'a', you use the "if" statement for that
and if your first item in your list is not equal to the string 'a', then use the "else" statement to print that item
see the code from Rich Zimmerman for step by step clearity

Rich Zimmerman · Answer

The "items" list is passed into your function when it is called. So while you don't have an actual value for "items", you know it's going to be a list of values. So you want to run your function through it accordingly. 
like this:
Python
for item in items:
    # item is the value of the item in the array for each index, so item[0] is index 0 of the word that's being passed as 'item'
    if item[0] == 'a':
        continue
    else:
        print(item)

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Tafadzwa Masocha

Tafadzwa Masocha

hi guys

2 Answers

Rich Zimmerman

Rich Zimmerman

FHATUWANI Dondry MUVHANGO

FHATUWANI Dondry MUVHANGO