Help with Exceptions and While Loops

Question

I am just practicing trying to use Exceptions and While Loops at the same time and I have ran into a problem.

try:
    number = int(input("choose a number below 10. "))
    while number > 10:
        number = int(input("choose smaller than 10! "))
except ValueError:
    print("error")
    number = int(input("you must choose a number. "))
    while number > 10:
        number = int(input("you must choose a number below 10. "))
    print("you chose {}.".format(number))
else:
    print("you chose {}".format(number))

This block of code runs how I would like it to apart from when the user inputs two strings in a row. My guess is that when the script enters into the except there is still the possibility of another ValueError. I feel like the only way of getting round this is to include an unlimited amount of "except ValueError:" blocks but this surely is not the way.

My question is, is this the best way to write this code and is the problem fixable? Thanks :)

Answer 1 · 2021-02-12T21:32:32Z

February 12, 2021 9:32pm

There are many ways to make the code more concise. Once metric is to look for comparisons done more that once, remembering Don't Repeat Yourself. If an invalid answer occurs in the except block then it will cause and error within the error and will not be handled.

# clear  passing condition
valid_answer = False
# loop until passing
while not valid_answer:
    try:
        number = int(input("choose a number below 10. "))
        if number < 10:
            valid_answer = True
        else:
            print("Number not smaller than 10! ")
    except ValueError:
        print("error")
        print("you must choose a number. ")
else:
    print("you chose {}".format(number))

Post back if you wish more help. Good luck!!

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aaron roberts

aaron roberts

Help with Exceptions and While Loops

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Chris Freeman

Chris Freeman