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2,748 PointsHelp On A Continue Task python
Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
This makes no sense to me, well to a degree. I've tried like everything i've been taught and just can't find a solution. Can someone give me the answer and explanation?
def loopy(items):
# Code goes here
1 Answer
Umesh Ravji
42,386 Pointsdef loopy(items):
for item in items:
if item[0] == 'a':
continue # skips the rest of the current iteration of the loop and moves onto the next
print(item)
Since you made it to the challenge you must have completed the previous one. Instead of using a break statement in the conditional check, this one involves using a continue statement in the conditional check.
Checking if the character at index 0 is an 'a' is done by the following line:
if item[0] == 'a':
If you want to know anymore, just ask :)