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Start your free trialRonit Mankad
12,166 PointsHelp!. Logical error
This is a little hard for me. Please help.
public class Example {
public static void main(String[] args) {
ShoppingCart cart = new ShoppingCart();
Product pez = new Product("Cherry PEZ refill (12 pieces)");
cart.addItem(pez, 5);
/* Since a quantity of 1 is such a common argument when adding a product to the cart,
* your fellow developers have asked you to make the following code work, as well as keeping
* the ability to add a product and a quantity.
*/
Product dispenser = new Product("Yoda PEZ dispenser");
/* Uncomment the line following this comment,
after adding a new method using method signatures,
to solve their request in ShoppingCart.java
*/
cart.addItem(dispenser);
}
}
public class ShoppingCart {
public void addItem(Product item) {
String ch=console.readLine("Do you want more than 1 piece?. Press 'Y' for yes and 'N' for no\n");
if(ch.equals('Y')) {
int quantity=System.getLine("How many items do you want?");
System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
/* Other code omitted for clarity. Please imagine
lots and lots of code here. Don't repeat it.
*/
}else {
System.out.printf("Adding 1 of %s to your cart\n",item.getName());
}
}
}
public class Product {
/* Other code omitted for clarity, but you could imagine
it would store price, options like size and color
*/
private String mName;
public Product(String name) {
mName = name;
}
public String getName() {
return mName;
}
}
1 Answer
anil rahman
7,786 PointsHi all i did was this:
public void addItem(Product item) { //make new method but ignoring adding a quantity just add item
System.out.printf("Adding %d of %s to the cart.%n", 1, item.getName());
//now instead of saying adding quantity it says adding 1
}
Ronit Mankad
12,166 PointsRonit Mankad
12,166 PointsThank you...making another method with just the item works!