Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
SAIADITHYA CUMBULAM
688 Pointshelp
def loopy(items): for num in items: if items.index[0] is 'a': continue print(num)
def loopy(items):
for num in items:
if items.index[0] is 'a':
continue
print(num)
2 Answers
Mark Ihrig
19,966 PointsYour code is the following:
def loopy(items):
for num in items:
if items.index[0] is 'a':
continue
print(num)
Your third line in your code has if items.index[0] is 'a': You have "items", and it should be "num". You don't need to use the word .index, the brackets with zero inside is all that is needed. The square brackets are the indexing operator. num[0] returns the first item in the array num. The word "is" will work for the quiz, but I have seen others use "==" instead. The word "is" will return True if two variables point to the same object, == if the objects referred to by the variables are equal. Both of the codes below will work for this quiz.
def loopy(items):
for num in items:
if num[0] is 'a':
continue
print(num)
or
def loopy(items):
for num in items:
if num[0] == 'a':
continue
print(num)
SAIADITHYA CUMBULAM
688 PointsThank you so much :)
Mark Ihrig
19,966 PointsYou are welcome!
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsIn this case, using
==is preferred.isshould be used when comparing if two objects are literally the same object in memory.