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Makan Fofana
Courses Plus Student 1,773 PointsHaving some trouble with this
Instructions Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through every item in items. If the current item's index 0 is the letter "a", continue to the next one. Otherwise, print out every member of items.
def loopy(items):
for item in items:
if item.index(0) == "a":
continue
print(items)
2 Answers
Anish Walawalkar
8,534 PointsHey Makan, Anish here again
def loopy(items):
for item in items:
if item[0] == 'a':
continue
print(item)
Afrid Mondal
6,255 PointsHey Makan, to see the value of index 0 you just have to write [0] followed by the item, not the index by itself. Everything rest is fine...
def loopy(items):
# Code goes here
for item in items:
if item[0] == "a":
continue
else:
print(item)
Makan Fofana
Courses Plus Student 1,773 PointsPerfect.
Makan Fofana
Courses Plus Student 1,773 PointsMakan Fofana
Courses Plus Student 1,773 PointsPerfect.