Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Break

David Sheridan
David Sheridan
8,579 Points

Having issues breaking out of the loop

Im having issues breaking out of the loop and I'm sure its something stupid i'm missing.

breaks.py
def loopy(items):
    # Code goes here
    for item in items:
        print(items)
        if items == "STOP":
            break

3 Answers

Pritesh singh
Pritesh singh
822 Points

it should be like this: def loopy(items): # Code goes here for item in items: if items == "STOP": break else: print(items)

Pritesh singh
Pritesh singh
822 Points

JUST READ THE QUESTION , after satisfying the condition then print.

Pritesh singh
Pritesh singh
822 Points

break should probably be in a while loop add (while True:)

David Sheridan
David Sheridan
8,579 Points

I tried wrapping the for loop and everything below inside a while look and got "Took to long to run"