Handling Exceptions Java

Question

I really tried everything. Can someon please point out what I'm doing wrong??

Protect the call to kart.drive by handling the IllegalArgumentException that is thrown when not enough battery remains. Print out the message from the exception to the screen as you catch the exception.

Example.java

class Example {

  public static void main(String[] args) {
    GoKart kart = new GoKart("purple");
    if (kart.isBatteryEmpty()) {
      System.out.println("The battery is empty");
    }
    kart.drive(42);
  }
try {
  kart.drive(42).

}
 catch(Exception e) {
 }

}

GoKart.java

class GoKart {
  public static final int MAX_BARS = 8;
  private int barCount;
  private String color;
  private int lapsDriven;

  public GoKart(String color) {
    this.color = color;
  }

  public String getColor() {
    return color;
  }

  public void charge() {
    barCount = MAX_BARS;
  }

  public boolean isBatteryEmpty() {
    return barCount == 0;
  }

  public boolean isFullyCharged() {
    return MAX_BARS == barCount;
  }

  public void drive() {
    drive(1);
  }

  public void drive(int laps) {
    if (laps > barCount) {
      throw new IllegalArgumentException("Not enough battery remains");
    }
    lapsDriven += laps;
    barCount -= laps;
  }
try { 
  kart.drive(42).
} catch(IllegalArgumentException iae) {

  system.out.println ( iae );
}
}

Answer 1 · 2017-03-25T10:44:42Z

March 25, 2017 10:44am

HI there,

You want to surround the existing call to drive with the try block, then create the catch. You are catching an IllegalAgumentException, specifically, in this case. Print that error out inside the catch block. That looks like:

    try {
      kart.drive(42); // existing line
    } catch(IllegalArgumentException e) {
      System.out.println(e);
    }    
  }

I hope that helps,

Steve.

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JJ T

JJ T

Handling Exceptions Java

1 Answer

Steve Hunter

Steve Hunter