Hand challenge in Python

Question

Hi Guys!

For this challenge, is there a way to pass the second challenge of instantiating multiple D20 dices by using yield? I've tried to but can't seem to pass it. Any help would be appreciated! Thanks!

dice.py

import random


class Die:
    def __init__(self, sides=2):
        if sides < 2:
            raise ValueError("Can't have fewer than two sides")
        self.sides = sides
        self.value = random.randint(1, sides)

    def __int__(self):
        return self.value

    def __add__(self, other):
        return int(self) + other

    def __radd__(self, other):
        return self + other

class D20(Die):
    def __init__(self, sides=20):
        super().__init__(sides)

hands.py

from dice import D20


class Hand(list):
    @property
    def total(self):
        return sum(self)

    @classmethod
    def roll(cls=D20, count):
        for _ in range(count):
            yield cls()

Answer 1 · 2020-04-01T13:29:31Z

April 1, 2020 1:29pm

This isn't a good application for "yield". That would be for a situation where calling a method would do only part of a job and calling it more times would do other parts of the same job.

This method should produce a completely loaded instance each time it is called.

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Ekenedilichukwu Osubor

Ekenedilichukwu Osubor

Hand challenge in Python

1 Answer

Steven Parker

Steven Parker