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Java

Posted by Victor Curtis Jr
Victor Curtis Jr
5,268 Points

Getting Two Errors Not Sure How to Fix

The compiler is giving me two errors and I'm not sure what I'm doing wrong. Here is my code:

public class Hangman {

  public static void main(String[] args) {
    // Your incredible code goes here...
    if (args.length == 0) {
      System.out.println("Usage:   java Hangman <answer>");
      System.err.println("answer is required");
      System.exit(1);
    }
    Game game = new Game(args[0]);
    Prompter prompter = new Prompter(game);
    while (game.getRemainingTries() > 0) && !game.isWon()) {
      prompter.displayProgress();
      prompter.promptForGuess();
    }

    prompter.displayOutcome(); 
   }
}

Here is what the compiler says:

treehouse:~/workspace$ javac Hangman.java
Picked up JAVA_TOOL_OPTIONS: -Xmx128m
Picked up _JAVA_OPTIONS: -Xmx128m
Hangman.java:12: error: illegal start of expression
while (game.getRemainingTries() > 0) && !game.isWon()) {
^
Hangman.java:12: error: ';' expected
while (game.getRemainingTries() > 0) && !game.isWon()) {
^
2 errors

David Pollard
David Pollard
4,324 Points
David Pollard
David Pollard
4,324 Points

I may be wrong, but are the parenthesis correct here :-

while (game.getRemainingTries() > 0) && !game.isWon()) {

Should it be ....

while ((game.getRemainingTries() > 0) && !game.isWon()) {

hth

dp

1 Answer

alastair cooper
alastair cooper
30,617 Points
alastair cooper
alastair cooper
30,617 Points

both expressions should be in the if parentheses, like so...

while (game.getRemainingTries() > 0 && !game.isWon()) {

The second error is probably caused by the compiler expecting a semi-colon because you closed the parentheses too early (although you would think it would expect an opening brace!)

hope this helps