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iOS Protocols in Swift Protocol Basics Protocols With Methods

Posted by Victor O'Rourke
Victor O'Rourke
2,387 Points

Getting this to take value of enum Color as argument

So i am doing this challenge and have tried running this with a switch statement i thought was right and then this maybe right if else. What im a little confused on is how to take the value of color as an argument. The wording on this is tripping me up

protocols.swift 
// Declare protocol here
protocol ColorSwitchable {
func switchColor (_ color) _> String
if bannanas = Color.rgb(23, 23, 23, 23)
print("bum") else print ("cool")


}


enum LightState {
  case on, off
}

enum Color {
  case rgb(Double, Double, Double, Double)
  case hsb(Double, Double, Double, Double)
}

class WifiLamp {
  let state: LightState
  var color: Color

  init() {
    self.state = .on
    self.color = .rgb(0,0,0,0)
  }
}

1 Answer

Nick Frozz
Nick Frozz
31,289 Points
Nick Frozz
Nick Frozz
31,289 Points

Part 1/2 of this challenge is asking us to create a protocol named ColorSwitchable; You got it:

protocol ColorSwitchable {
}

Then it requires a func named "switchColor" with an omitted external argument "_", argument named "color" that has a value of "Color" inside of it, so you almost got it but forgot about a value. After 2nd step we're getting:

protocol ColorSwitchable {

func switchColor(_ color: Color)

}

Part 2/2. Asking us to adopt the ColorSwitchable protocol. To conform the protocol we need to use EVERY method and argument that our protocol has. In our case, it's a single function "switchColor". (function always goes before init.) :

class WifiLamp: ColorSwitchable {

let state: LightState

var color: Color

func switchColor(_ color: Color) {

self.color = color    //here we are simply setting a color to the new one.

}

init() {

self.state = .on
self.color = .rgb(0,0,0,0)

}
}