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Start your free trialBrittney Coble
16,474 PointsGetting "Target not found in list" for target 6
Here is my code. I cannot understand why 6 produces "Target not found in list" message when calling the last verify.
def linear_search(list, target): """ Returns the index position of the target if found, else returns None. """
for i in range(0, len(list)): if list[i] == target: return i return None
def verify(index): if index is not None: print("Target found at index: ", index) else: print("Target not found in list")
numbers = [1,2,3,4,5,6,7,8,9,10]
result = linear_search(numbers, 12) verify(result)
result = linear_search(numbers, 6) verify(result)
2 Answers
KRIS NIKOLAISEN
54,971 PointsThe return statement exits immediately, so in linear_search anything other than the first list item (1) will return target not found. Think of return None
as an else statement that will only execute once and halt the loop.
Suhas Nukala
2,786 PointsRemove 'return None' in linear_search function.
Brittney Coble
16,474 PointsBrittney Coble
16,474 PointsThank you! That helped.